Equation 1: 8x+2y=308x+2y=30Equation 2: 7x+2y=247x+2y=24Which variable pair should we try to eliminate?The x's because the coefficients are the same.The y's because the coefficients are the same.The x's because the coefficients are different?The y's because the coefficients are different?Now that we've eliminated the variable pair, what is the resulting equation?15y+4y=5415y+4y=54x+4y=54x+4y=544y=64y=6Consider the following system of equations:Equation 1: 8x+2y=308x+2y=30Equation 2: 7x+2y=247x+2y=24What is the solution to the system?(6,8)(6,-9)(1,11)(0,12)

Answer:Part a) We should try to eliminate the y's because the coefficients are the samePart b) The solution is the point (6,-9)Step-by-step explanation:Part a) Which variable pair should we try to eliminate?we have[tex]8x+2y=30[/tex] ----> equation 1[tex]7x+2y=24[/tex] ----> equation 2Solve by eliminationWe should try to eliminate the y's because the coefficients are the samePart b) What is the solution to the system?Multiply equation 2 by -1 both sides[tex]-1(7x+2y)=-1(24)[/tex][tex]-7x-2y=-24[/tex] -----> equation 3Adds equation 1 and equation 3[tex]8x+2y=30\\-7x-2y=-24\\-------\\8x-7x=30-24\\x=6[/tex]Find the value of y[tex]8x+2y=30[/tex[tex]8(6)+2y=30[/tex][tex]2y=30-48[/tex][tex]y=-9[/tex]The solution is the point (6,-9)