What is the true solution to the logarithmic equation below?

Answer:x = 4/9CStep-by-step explanation:log_2(6x/) - log_2(x^(1/2) = 2         Givenlog_2(6x/x^1/2) = 2                         Subtracting logs means division log_2(6 x^(1 - 1/2)) = 2                     Subtract powers on the x slog_2(6 x^(1/2) ) = 2                         Take the anti log of both sides6 x^1/2 = 2^2                                    Combine the right6 x^1/2 = 4                                        Divide by 6  x^1/2 = 4/6 = 2/3                               which gives 2/3 now square both sidesx = (2/3)^2                                       x = 4/9